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lots of stuff, python names, xquery to html, xml regex clean-ish

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<xml><p> Host Element Fusion</p>
<p> Unpublished Work
Copyright (c) 1990
Earl <ent type='PERSON'>Laurence Lovings</ent></p>
<p>1. Proton (1 <ent type='ORG'>Hydrogen</ent> 1) Energy: 938.3 <ent type='PERSON'>Mev</ent> = 1.007825 amu
2. Neutron (1 Neutron 0) Energy: 939.6 <ent type='PERSON'>Mev</ent> = 1.008665 amu
3. <ent type='GPE'>Deuterium</ent> (2 <ent type='ORG'>Hydrogen</ent> 1) = 2.014102 amu
4. [(1 Neutron 0) + (1 <ent type='ORG'>Hydrogen</ent> 1) - electron] =
(939.6 <ent type='PERSON'>Mev</ent> + 938.3 <ent type='PERSON'>Mev</ent> - .511 <ent type='PERSON'>Mev</ent>) = 1877.389 <ent type='PERSON'>Mev</ent> =
2.015447128 amu
5. [(1 Neutron 0) - (1 <ent type='ORG'>Hydrogen</ent> 1) + electron] =
(939.6 <ent type='PERSON'>Mev</ent> - 938.3 <ent type='PERSON'>Mev</ent> + .511 <ent type='PERSON'>Mev</ent>) = 1.811 <ent type='PERSON'>Mev</ent> =
1.9441763 x 10 - 03 amu
6. (105 <ent type='ORG'>Palladium</ent> 46) = 104.905064 amu
7. (103 <ent type='ORG'>Rhodium</ent> 45) = 102.905511 amu</p>
<p>The host element fusion experiment begins with a <ent type='ORG'>Palladium</ent>
electrode submersed in <ent type='GPE'>Deuterium</ent>. A energy source is supplied,
which enables the fusion process to begin. My theory on this
subject is explained below:</p>
<p>The <ent type='GPE'>Deuterium</ent> atoms are allowed inside the <ent type='ORG'>Palladium</ent> electrode due
to the electric field on the electrode. Once the <ent type='GPE'>Deuterium</ent> atoms
are inside, the <ent type='GPE'>Deuterium</ent> causes the <ent type='ORG'>Palladium</ent> to become unstable.
This is done by this process:</p>
<p>[ (105 Pd 46 - (1 Neutron 0 + 1 <ent type='ORG'>Hydrogen</ent> 1 - electron) +
(1 Neutron 0 - 1 <ent type='ORG'>Hydrogen</ent> 1 + electron)] or,
[ 104.905064 amu - 2.015447128 amu + 1.9441763 x 10-03 amu] =
102.8916 amu.</p>
<p>The closest element <ent type='ORG'>Palladium</ent> can try to become stable is
(103 <ent type='ORG'>Rhodium</ent> 45).</p>
<p>Take <ent type='ORG'>Palladium</ent>'s new mass and subtract it with <ent type='ORG'>Rhodium</ent>'s mass.
(103 <ent type='ORG'>Rhodium</ent> 45) - 102.8916 amu, or
102.905511 amu - 102.8916 amu = 1.394653 x 10-02 amu.</p>
<p>To find out how many electrons that is equivalent to:
(1.394653 x 10-02 amu x 931.5 <ent type='PERSON'>Mev</ent>/amu)/(.511 <ent type='PERSON'>Mev</ent>/electrons) =
25.42309 electrons</p>
<p>This is the amount of electrons required to be ionized to enable
host element fusion with <ent type='GPE'>Deuterium</ent>. </p>
<p>That is the first process of host element fusion. </p>
<p>The second process begins when the ionized electrons from the
palladium atom shields the deuterium atoms to allow host element
fusion.</p>
<p> The Equation:</p>
<p>Q = [(2 <ent type='ORG'>Hydrogen</ent> 1) + (2 <ent type='ORG'>Hydrogen</ent> 1) + (25.423 e) -
(1877.389 <ent type='PERSON'>Mev</ent>) + (1.811 <ent type='PERSON'>Mev</ent>) - (2 <ent type='ORG'>Hydrogen</ent> 1)] x 931.5 <ent type='PERSON'>Mev</ent> or,</p>
<p>Q = [(2.014102 amu + 2.014102 amu + .01394653 amu - 2.015447 amu
+ 1.944176 x 10-03 amu - 2.014102 amu)] x 931.5 <ent type='PERSON'>Mev</ent></p>
<p>Q = 13.55 <ent type='PERSON'>Mev</ent></p>
<p>You must realize for this process to work for host element fusion,
you have to have a host element before <ent type='GPE'>Deuterium</ent> will fuse.
My equation also theoretically works for known <ent type='GPE'>Deuterium</ent> fusion
processes.</p>
<p> Known Equation:</p>
<p>1. [(2 <ent type='ORG'>Hydrogen</ent> 1) + (2 <ent type='ORG'>Hydrogen</ent> 1)] -&gt; (3 Helium 2) +
(1 Neutron 0)] = or,</p>
<p> [(2.014102 amu + 2.014102 amu - 3.016030 amu - 1.008665 amu) x
(931.5 <ent type='PERSON'>Mev</ent>/amu)] = Q = 3.27 <ent type='PERSON'>Mev</ent></p>
<p>My Equation: </p>
<p>Host Element = (3 Helium 2) + (1 Neutron 0)
[(3 Helium 2) + (1 Neutron 0) - 1877.389 <ent type='PERSON'>Mev</ent> + 1.811 <ent type='PERSON'>Mev</ent>] =
[3.016030 amu + 1.008665 amu - 2.015447 amu + 1.944176x10-03 amu]
= 2.011192 amu</p>
<p>The element whose mass is closest to the new unstable "element" is
(2 <ent type='ORG'>Hydrogen</ent> 1)</p>
<p>(2.014102 amu) - 2.011192 amu = 2.909899 x 10-03 amu excess mass
convert to electrons</p>
<p>(2.909899 x 10-03 amu x 931.5 <ent type='PERSON'>Mev</ent>/amu) /(.511 <ent type='PERSON'>Mev</ent>/electrons) =
5.304445 electrons</p>
<p>Now the fusion of <ent type='GPE'>Deuterium</ent> atoms
[(2 <ent type='ORG'>Hydrogen</ent> 1) + (2 <ent type='ORG'>Hydrogen</ent> 1) + 5.30444e - 1877.389 <ent type='PERSON'>Mev</ent>
+ 1.811 <ent type='PERSON'>Mev</ent> - (2 <ent type='ORG'>Hydrogen</ent> 1)] x 931.5 <ent type='PERSON'>Mev</ent> =
[(2.014102 amu + 2.014102 amu + 2.909899x10-03 amu - 2.015447 amu
+ 1.944176x10-03 amu - 2.014102 amu)] x (931.5 <ent type='PERSON'>Mev</ent>/amu)</p>
<p>Q = 3.27 <ent type='PERSON'>Mev</ent></p>
<p> Known Equation:</p>
<p>2. [(2 <ent type='ORG'>Hydrogen</ent> 1) + (2 <ent type='ORG'>Hydrogen</ent> 1) -&gt; (4 Helium 2)] = or,
[(2.014102 amu + 2.014102 amu - 4.002603 amu)] x
(931.5 <ent type='PERSON'>Mev</ent>/amu) = Q = 23.85 <ent type='PERSON'>Mev</ent>
My Equation: </p>
<p>Host Element = (4 Helium 2)
[(4 Helium 2) - 1877.389 <ent type='PERSON'>Mev</ent> + 1.811 <ent type='PERSON'>Mev</ent>] =
[(4.002603 amu - 2.015447 amu + 1.944176x10-03 amu)] = 1.9891 amu</p>
<p>The element whose mass is closest to the new unstable "element" is
(2 <ent type='ORG'>Hydrogen</ent> 1)</p>
<p>(2.014102 amu) - 1.9891 amu = 2.500188 x 10-02 amu excess mass
convert to electrons</p>
<p>(2.500188 x 10-02 amu x 931.5 <ent type='PERSON'>Mev</ent>/amu) /(.511 <ent type='PERSON'>Mev</ent>/electrons) =
45.57585 electrons</p>
<p>Now the fusion of <ent type='GPE'>Deuterium</ent> atoms
[(2 <ent type='ORG'>Hydrogen</ent> 1) + (2 <ent type='ORG'>Hydrogen</ent> 1) + 45.58 electrons - 1877.389 <ent type='PERSON'>Mev</ent>
+ 1.811 <ent type='PERSON'>Mev</ent> - (2 <ent type='ORG'>Hydrogen</ent> 1)] x 931.5 <ent type='PERSON'>Mev</ent> =
[(2.014102 amu + 2.014102 amu + 2.500188x10-02 amu - 2.015447 amu
+ 1.944176x10-03 amu - 2.014102 amu)] x (931.5 <ent type='PERSON'>Mev</ent>/amu) =</p>
<p>Q = 23.85 <ent type='PERSON'>Mev</ent></p>
<p> Known Equation:</p>
<p>3. [(2 <ent type='ORG'>Hydrogen</ent> 1) + (2 <ent type='ORG'>Hydrogen</ent> 1) -&gt; (3 <ent type='ORG'>Hydrogen</ent> 1) +
(1 <ent type='ORG'>Hydrogen</ent> 1) = or,</p>
<p>[(2.014102 amu + 2.014102 amu - 3.016050 amu - 1.007825 amu)] x
(931.5 <ent type='PERSON'>Mev</ent>/amu) = Q = 4.03 <ent type='PERSON'>Mev</ent></p>
<p>My Equation: </p>
<p>Host Element = (3 <ent type='ORG'>Hydrogen</ent> 1) + (1 <ent type='ORG'>Hydrogen</ent> 1)
[(3 <ent type='ORG'>Hydrogen</ent> 1) + ( 1 <ent type='ORG'>Hydrogen</ent> 1) - 1877.389 <ent type='PERSON'>Mev</ent> + 1.811 <ent type='PERSON'>Mev</ent>] =
[3.016050 amu + 1.007825 amu - 2.015447 amu + 1.944176x10-03 amu]
= 2.010372 amu</p>
<p>The element whose mass is closest to the new unstable "element" is
(2 <ent type='ORG'>Hydrogen</ent> 1)</p>
<p>(2.014102 amu - 2.010372 amu) = 3.729582x10-03 amu excess mass
convert to electrons</p>
<p>(3.729582x10-03 amu x 931.5 <ent type='PERSON'>Mev</ent>/amu)/(.511 <ent type='PERSON'>Mev</ent>/electrons) =
6.798641 electrons</p>
<p>Now the fusion of <ent type='GPE'>Deuterium</ent> atoms
[(2 <ent type='ORG'>Hydrogen</ent> 1) + (2 <ent type='ORG'>Hydrogen</ent> 1) + 6.799 electrons - 1877.389 <ent type='PERSON'>Mev</ent>
+ 1.811 <ent type='PERSON'>Mev</ent> - (2 <ent type='ORG'>Hydrogen</ent> 1)] x 931.5 <ent type='PERSON'>Mev</ent> =
[(2.014102 amu + 2.014102 amu + 3.7296x10-03 amu - 2.015447 amu +
1.944176x10-03 amu - 2.014102 amu)] x (931.5 <ent type='PERSON'>Mev</ent>/amu) =
Q = 4.03 <ent type='PERSON'>Mev</ent></p>
<p> Known Equation:</p>
<p>4. [(1 <ent type='ORG'>Hydrogen</ent> 1) + (1 <ent type='ORG'>Hydrogen</ent>) -&gt; (2 <ent type='ORG'>Hydrogen</ent> 1) +(electron)=
[(1.007825 amu + 1.007825 amu - 2 electrons - 2.014102 amu)]
x (931.5 <ent type='PERSON'>Mev</ent>/amu) = Q = .42 <ent type='PERSON'>Mev</ent></p>
<p>My Equation:</p>
<p>Host Element = (2 <ent type='ORG'>Hydrogen</ent> 1)
[(2 <ent type='ORG'>Hydrogen</ent> 1) - 1877.389 <ent type='PERSON'>Mev</ent> + 1.811 <ent type='PERSON'>Mev</ent>] =
[(2.014102 amu - 2.015447128 amu + 1.9441763x10-03 amu)] =
5.990302x10-04 amu</p>
<p>The element whose mass is closest to the new unstable "element"
is (1 <ent type='ORG'>Hydrogen</ent> 1)</p>
<p>(1.007825 amu - 5.990302x10-03 amu) = 1.007226 amu excess mass
convert to neutrinos</p>
<p>(1.007226 amu x 931.5 <ent type='PERSON'>Mev</ent>/amu) / (.42 <ent type='PERSON'>Mev</ent>/neutrinos) =
2233.884 neutrinos</p>
<p>Now the fusion of 1 <ent type='ORG'>Hydrogen</ent> 1 atoms</p>
<p>[(1 <ent type='ORG'>Hydrogen</ent> 1) + (1 <ent type='ORG'>Hydrogen</ent> 1) + 2234 neutrinos - 2 electrons
- 1877.389 <ent type='PERSON'>Mev</ent> + 1.811 <ent type='PERSON'>Mev</ent> - (1 <ent type='ORG'>Hydrogen</ent>)] x 931.5 <ent type='PERSON'>Mev</ent>/amu =
[(1.007825 amu + 1.007825 amu + 1.007226 amu - .001097 amu
-2.015447128 amu + 1.9441763x10-03 amu - 1.007825 amu)]
x 931.5 <ent type='PERSON'>Mev</ent>/amu = Q = .42 <ent type='PERSON'>Mev</ent>
</p></xml>