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Tidy links, and lint (#2435)

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Tidies up a number of things:

- Outdated links that redirect
- Dead links
- Remove unnecessary parameters eg "en" and "en-US"
- Shortened amazon, apps.apple.com, reddit links
- Removed trailing /
- Remove www (except for PG assets)
- Optimize unoptimized SVGs and remove xml declarations
- Lint yaml, md files

Co-Authored-By: Daniel Gray <dngray@privacyguides.org>
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12
docs/basics/passwords-overview.md
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@ -54,13 +54,13 @@ To generate a diceware passphrase using real dice, follow these steps:
<div class="admonition Note" markdown>
<p class="admonition-title">Note</p>
These instructions assume that you are using [EFF's large wordlist](https://www.eff.org/files/2016/07/18/eff_large_wordlist.txt) to generate the passphrase, which requires five dice rolls per word. Other wordlists may require more or less rolls per word, and may require a different amount of words to achieve the same entropy.
These instructions assume that you are using [EFF's large wordlist](https://eff.org/files/2016/07/18/eff_large_wordlist.txt) to generate the passphrase, which requires five dice rolls per word. Other wordlists may require more or less rolls per word, and may require a different amount of words to achieve the same entropy.
</div>
1. Roll a six-sided die five times, noting down the number after each roll.
2. As an example, let's say you rolled `2-5-2-6-6`. Look through the [EFF's large wordlist](https://www.eff.org/files/2016/07/18/eff_large_wordlist.txt) for the word that corresponds to `25266`.
2. As an example, let's say you rolled `2-5-2-6-6`. Look through the [EFF's large wordlist](https://eff.org/files/2016/07/18/eff_large_wordlist.txt) for the word that corresponds to `25266`.
3. You will find the word `encrypt`. Write that word down.
@ -75,20 +75,20 @@ You should **not** re-roll words until you get a combination of words that appea
If you don't have access to or would prefer to not use real dice, you can use your password manager's built-in password generator, as most of them have the option to generate diceware passphrases in addition to regular passwords.
We recommend using [EFF's large wordlist](https://www.eff.org/files/2016/07/18/eff_large_wordlist.txt) to generate your diceware passphrases, as it offers the exact same security as the original list, while containing words that are easier to memorize. There are also [other wordlists in different languages](https://theworld.com/~reinhold/diceware.html#Diceware%20in%20Other%20Languages|outline), if you do not want your passphrase to be in English.
We recommend using [EFF's large wordlist](https://eff.org/files/2016/07/18/eff_large_wordlist.txt) to generate your diceware passphrases, as it offers the exact same security as the original list, while containing words that are easier to memorize. There are also [other wordlists in different languages](https://theworld.com/~reinhold/diceware.html#Diceware%20in%20Other%20Languages|outline), if you do not want your passphrase to be in English.
<details class="note" markdown>
<summary>Explanation of entropy and strength of diceware passphrases</summary>
To demonstrate how strong diceware passphrases are, we'll use the aforementioned seven word passphrase (`viewable fastness reluctant squishy seventeen shown pencil`) and [EFF's large wordlist](https://www.eff.org/files/2016/07/18/eff_large_wordlist.txt) as an example.
To demonstrate how strong diceware passphrases are, we'll use the aforementioned seven word passphrase (`viewable fastness reluctant squishy seventeen shown pencil`) and [EFF's large wordlist](https://eff.org/files/2016/07/18/eff_large_wordlist.txt) as an example.
One metric to determine the strength of a diceware passphrase is how much entropy it has. The entropy per word in a diceware passphrase is calculated as $\text{log}_2(\text{WordsInList})$ and the overall entropy of the passphrase is calculated as $\text{log}_2(\text{WordsInList}^\text{WordsInPhrase})$.
Therefore, each word in the aforementioned list results in ~12.9 bits of entropy ($\text{log}_2(7776)$), and a seven word passphrase derived from it has ~90.47 bits of entropy ($\text{log}_2(7776^7)$).
The [EFF's large wordlist](https://www.eff.org/files/2016/07/18/eff_large_wordlist.txt) contains 7776 unique words. To calculate the amount of possible passphrases, all we have to do is $\text{WordsInList}^\text{WordsInPhrase}$, or in our case, $7776^7$.
The [EFF's large wordlist](https://eff.org/files/2016/07/18/eff_large_wordlist.txt) contains 7776 unique words. To calculate the amount of possible passphrases, all we have to do is $\text{WordsInList}^\text{WordsInPhrase}$, or in our case, $7776^7$.
Let's put all of this in perspective: A seven word passphrase using [EFF's large wordlist](https://www.eff.org/files/2016/07/18/eff_large_wordlist.txt) is one of ~1,719,070,799,748,422,500,000,000,000 possible passphrases.
Let's put all of this in perspective: A seven word passphrase using [EFF's large wordlist](https://eff.org/files/2016/07/18/eff_large_wordlist.txt) is one of ~1,719,070,799,748,422,500,000,000,000 possible passphrases.
On average, it takes trying 50% of all the possible combinations to guess your phrase. With that in mind, even if your adversary is capable of ~1,000,000,000,000 guesses per second, it would still take them ~27,255,689 years to guess your passphrase. That is the case even if the following things are true: