This commit is contained in:
Mia von Steinkirch 2019-05-13 13:50:21 -07:00
parent bb6afce467
commit 85ecba5ace
2 changed files with 103 additions and 0 deletions

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#!/bin/python
"""
Write a function that returns a list of all the duplicate files.
the first item is the duplicate file
the second item is the original file
For example:
[('/tmp/parker_is_dumb.mpg', '/home/parker/secret_puppy_dance.mpg'),
('/home/trololol.mov', '/etc/apache2/httpd.conf')]
You can assume each file was only duplicated once.
"""
import os
import hashlib
def find_duplicate_files(starting_directory):
files_seen_already = {}
stack = [starting_directory]
duplicates = []
while len(stack):
current_path = stack.pop()
if os.path.isdir(current_path):
for path in os.listdir(current_path):
full_path = os.path.join(current_path, path)
stack.append(full_path)
else:
file_hash = sample_hash_file(current_path)
current_last_edited_time = os.path.getmtime(current_path)
if file_hash in files_seen_already:
existing_last_edited_time, existing_path = files_seen_already[file_hash]
if current_last_edited_time > existing_last_edited_time:
duplicates.append((current_path, existing_path))
else:
duplicates.append((existing_path, current_path))
files_seen_already[file_hash] = (current_last_edited_time, current_path)
else:
files_seen_already[file_hash] = (current_last_edited_time, current_path)
return duplicates
def sample_hash_file(path):
num_bytes_to_read_per_sample = 4000
total_bytes = os.path.getsize(path)
hasher = hashlib.sha512()
with open(path, 'rb') as file:
if total_bytes < num_bytes_to_read_per_sample * 3:
hasher.update(file.read())
else:
num_bytes_between_samples = (
(total_bytes - num_bytes_to_read_per_sample * 3) / 2
)
for offset_multiplier in range(3):
start_of_sample = (
offset_multiplier
* (num_bytes_to_read_per_sample + num_bytes_between_samples)
)
file.seek(start_of_sample)
sample = file.read(num_bytes_to_read_per_sample)
hasher.update(sample)
return hasher.hexdigest()

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#!/bin/python
"""
Grab Apple's stock prices and put them in a list called stock_prices, where:
The indices are the time (in minutes) past trade opening time, which was 9:30am local time.
The values are the price (in US dollars) of one share of Apple stock at that time.
So if the stock cost $500 at 10:30am, that means stock_prices[60] = 500.
Write an efficient function that takes stock_prices and returns the best profit I could have made from one purchase and one sale of one share.
"""
def apple_stock_profit(stock_prices):
min_s, max_s = max(stock_prices), 0
while stock_prices:
stock = stock_prices.pop()
min_s = min(min_s, stock)
max_s = max(max_s, stock)
return max_s - min_s
stock_prices = [10, 7, 5, 8, 11, 9]
print apple_stock_profit(stock_prices)
print("Should return 6 (buying for $5 and selling for $11)")