mirror of
https://github.com/autistic-symposium/master-algorithms-py.git
synced 2025-04-30 04:36:08 -04:00
Update README.md
This commit is contained in:
parent
ea039f5514
commit
5ec8587911
@ -9,14 +9,21 @@
|
|||||||
|
|
||||||
<br>
|
<br>
|
||||||
|
|
||||||
* if the depth of the tree is too large, stack overflow might happen, therefore iterative solutions might be better.
|
* **breath-first search**:
|
||||||
* **in-order** are similar to breath-first search (level order problems)
|
- similar to pre-order, but work with queue (level order problem)
|
||||||
- work with queues
|
* **depth-first search**:
|
||||||
* **pre-order** is top-down (parameters are passed down to children).
|
* if the depth of the tree is too large, stack overflow might happen, therefore iterative solutions might be better.
|
||||||
- work with stacks
|
* work with stacks
|
||||||
* **post-order** is a bottom-up solution (if you know the answer of the children, can you concatenate the answer of the nodes?):
|
* **in-order**:
|
||||||
- deletion process is always post-order: when you delete a node, you will delete its left child and its right child before you delete the node itself.
|
* left -> node -> right
|
||||||
- also, post-order is used in mathematical expressions as it's easier to write a program to parse a post-order expression. using a stack, each time when you meet a operator, you can just pop 2 elements from the stack, calculate the result and push the result back into the stack.
|
* **pre-order**
|
||||||
|
* node -> left -> right
|
||||||
|
* top-down (parameters are passed down to children).
|
||||||
|
* **post-order**
|
||||||
|
* left -> right -> node
|
||||||
|
* bottom-up solution (if you know the answer of the children, can you concatenate the answer of the nodes?):
|
||||||
|
- deletion process is always post-order: when you delete a node, you will delete its left child and its right child before you delete the node itself.
|
||||||
|
- also, post-order is used in mathematical expressions as it's easier to write a program to parse a post-order expression. using a stack, each time when you meet a operator, you can just pop 2 elements from the stack, calculate the result and push the result back into the stack.
|
||||||
|
|
||||||
|
|
||||||
<br>
|
<br>
|
||||||
|
Loading…
x
Reference in New Issue
Block a user