This commit is contained in:
Mia von Steinkirch 2019-05-12 18:00:11 -07:00
parent fa83f7e42a
commit 0d5e21b867
9 changed files with 148 additions and 2 deletions

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#!/usr/bin/env python

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#!/usr/bin/python
''' Clear a bit in a binary number.
Like the reverse of set bit:
1) first create a number filled of 1s,
with 0 at i (can create 0001000 and ~)
2) AND the number so it clears the ith bit
'''
def clear_bit(num, i):
mask = ~ (1 << i) # -0b10001
return bin(num & mask)
def clear_all_bits_from_i_to_0(num, i):
mask = ~ ( (1 << (i+1)) - 1)
return bin(num & mask)
def clear_all_bits_from_most_sig_to_1(num, i):
mask = ( 1 << i) -1
return bin(num & mask)
if __name__ == '__main__':
num = int('10010000', 2)
print clear_bit(num, 4) # '0b10000000'
num = int('10010011', 2)
print clear_all_bits_from_i_to_0(num, 2) # '0b10010000'
num = int('1110011', 2)
print clear_all_bits_from_most_sig_to_1(num, 2) #'0b11'

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#!/usr/bin/python
''' This method returns the number of bits that are necessary to change to convert two
numbers A and B:
1) XOR
2) count 1s
'''
def count_bits_swap2(a, b):
count = 0
m = a^b
while m:
count +=1
m = m & (m-1)
return count
def count_bits_swap(a, b):
m = a^b
return count_1s(m)
def count_1s(m):
count = 0
while m:
if m& 1 :
count +=1
m >>= 1
return count
if __name__ == '__main__':
a = int('10010000', 2)
b = int('01011010', 2)
print count_bits_swap(a, b) #4
print count_bits_swap2(a, b) #4

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#!/usr/bin/python
''' Set a bit in a binary number:
1) Shifts 1 over by i bits
2) make an OR with the number, only the value at bit i will change and all the others bit
of the mask are zero so will not affect the num
'''
def set_bit(num, i):
mask = 1 << i
return bin( num | mask )
if __name__ == '__main__':
num = int('0100100', 2)
print set_bit(num, 0) #'0b100101'
print set_bit(num, 1) #'0b100110'
print set_bit(num, 2) # nothing change '0b100100'
print set_bit(num, 3) #'0b101100'
print set_bit(num, 4) #'0b110100'
print set_bit(num, 5) # nothing change '0b100100'

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#!/usr/bin/python
''' This method merges set bit and clean bit:
1) first clear the bit at i using a mask such as 1110111
2) then shift the intended value v by i bits
3) this will create a number with bit i to v and all other to 0
4) finally update the ith bit with or
'''
def update_bit(num, i, v):
mask = ~ (1 << i)
return bin( (num & mask) | (v << i) )
if __name__ == '__main__':
num = int('10010000', 2)
print update_bit(num, 2, 1) # '0b10010100'

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#!/usr/bin/python
''' Given a real number between 0 and 1 (eg: 0.72), this method print the binary
representation. If the Number cannot be represented accurately in binary, with at
most 32 chars, print error:
'''
def get_float_rep(num):
if num >= 1 or num <= 0: return 'Error 1'
result = '.'
while num:
if len(result) >= 32: return 'Error 2', result
r = num*2
if r >= 1:
result += '1'
num = r - 1
else:
result += '0'
num = r
return result
if __name__ == '__main__':
print get_float_rep(0.72) #('Error 2', '.1011100001010001111010111000010')
print get_float_rep(0.1) # ('Error 2', '.0001100110011001100110011001100')
print get_float_rep(0.5) #'.1'

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#!/usr/bin/env python
""" """
In order to win the prize for most cookies sold, my friend Alice and In order to win the prize for most cookies sold, my friend Alice and
# I are going to merge our Girl Scout Cookies orders and enter as one unit. # I are going to merge our Girl Scout Cookies orders and enter as one unit.

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#!/usr/bin/env python
""" """
Write an efficient function that checks whether Write an efficient function that checks whether
any permutation of an input string is a palindrome. any permutation of an input string is a palindrome.

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# Write a function that takes a list of characters and reverses the letters in place. #!/usr/bin/env python
# O(n) time and O(1)O(1) space.
"""
Write a function that takes a list of characters and reverses the letters in place.
O(n) time and O(1)O(1) space.
"""
def reverse_in_place(char_list): def reverse_in_place(char_list):
return char_list[::-1] return char_list[::-1]